Better repository management. Purge packages to keep the desired number. Currently set to keep last five.

This commit is contained in:
Igor Pecovnik 2017-08-28 23:16:17 +02:00
parent 527acd3035
commit d6853e64db

View File

@ -29,7 +29,10 @@ ParseOptions() {
for release in "${DISTROS[@]}"; do
display_alert "Displaying repository contents for" "$release" "ext"
aptly repo show -with-packages -config=../config/aptly.conf $release | tail -n +7
aptly repo show -with-packages -config=../config/aptly.conf ${release}-desktop | tail -n +7
done
display_alert "Displaying repository contents for" "common utils" "ext"
aptly repo show -with-packages -config=../config/aptly.conf utils | tail -n +7
echo "done."
exit 0
;;
@ -42,6 +45,14 @@ ParseOptions() {
echo "done."
exit 0
;;
purge)
for release in "${DISTROS[@]}"; do
repo-remove-old-packages "$release" "armhf" "5"
repo-remove-old-packages "$release" "arm64" "5"
aptly -config=../config/aptly.conf -passphrase=$GPG_PASS publish update $release
done
exit 0
;;
*)
DisplayUsage
exit 0
@ -49,8 +60,36 @@ ParseOptions() {
esac
} # ParseOptions
# Removes old packages in the received repo
#
# $1: Repository
# $2: Architecture
# $3: Amount of packages to keep
repo-remove-old-packages() {
local repo=$1
local arch=$2
local keep=$3
for pkg in $(aptly repo search -config=../config/aptly.conf $repo "Architecture ($arch)" | grep -v "ERROR: no results" | sort -rV); do
local pkg_name=$(echo $pkg | cut -d_ -f1)
if [ "$pkg_name" != "$cur_pkg" ]; then
local count=0
local deleted=""
local cur_pkg="$pkg_name"
fi
test -n "$deleted" && continue
let count+=1
if [ $count -gt $keep ]; then
pkg_version=$(echo $pkg | cut -d_ -f2)
aptly repo remove -config=../config/aptly.conf $repo "Name ($pkg_name), Version (<= $pkg_version)"
deleted='yes'
fi
done
}
DisplayUsage() {
echo -e "Usage: repository show | update\n"
echo -e "Usage: repository show | update | purge\n"
echo -e "Purge removes all but last 5 versions\n"
} # DisplayUsage
ParseOptions "$@"